"Isoelectronic molecules and ions have identical bond orders." Explain by examples.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Isoelectronic species are those that contain the same total number of electrons. According to the Molecular Orbital Theory,if two or more diatomic molecules or ions are isoelectronic,they possess the same bond order.
Example-$1$: $F_{2}$ and $O_{2}^{2-}$ both contain $18$ electrons. Their bond order is $1$.
Example-$2$: $N_{2}$,$CO$,and $NO^{+}$ are isoelectronic,each containing $14$ electrons. They all exhibit a triple bond.
Molecule/ion $N_{2}, CO, NO^{+}$
Bond structure $N \equiv N, C \equiv O, N \equiv O^{+}$

Explore More

Similar Questions

The correct order of bond orders of $C_{2}^{2-}$,$N_{2}^{2-}$,and $O_{2}^{2-}$ is,respectively.

Select the correct set of statements regarding the molecular orbital theory of $O_2$:
$A$. Addition of an electron to $O_2$ decreases bond order.
$B$. Addition of an electron to $O_2$ increases bond order.
$C$. Removal of an electron from $O_2$ increases bond length.
$D$. Removal of an electron from $O_2$ decreases bond length.

Difficult
View Solution

$N_2$ and $O_2$ are converted into monocations,$N_2^+$ and $O_2^+$ respectively. Which of the following statements is wrong?

Match List-$I$ with List-$II$ and select the correct option:
List-$I$ (Molecule / ion)List-$II$ (Bond order)
$1$. $NO$$i$. $1.5$
$2$. $CO$$ii$. $2.0$
$3$. $O_2^{-}$$iii$. $2.5$
$4$. $O_2$$iv$. $3.0$

Among $KO_2$,$KAlO_2$,$CaO_2$ and $NO_2^+$,unpaired electron is present in

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo